2x^2+0.18x-0.018=0

Solution for 2x^2+0.18x-0.018=0 equation:

2x^2+0.18x-0.018=0

a = 2; b = 0.18; c = -0.018;
Δ = b2-4ac
Δ = 0.182-4·2·(-0.018)
Δ = 0.1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.18)-\sqrt{0.1764}}{2*2}=\frac{-0.18-\sqrt{0.1764}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.18)+\sqrt{0.1764}}{2*2}=\frac{-0.18+\sqrt{0.1764}}{4}
$